Any feedback?
Please rate this page
(search_result.php)
(0/150)

BRENDA support

Refine search

Search Reaction

show results
Don't show organism specific information (fast!)
Search organism in taxonomic tree (slow, choose "exact" as search mode, e.g. "mammalia" for rat,human,monkey,...)
(Not possible to combine with the first option)
Refine your search

Search term:

Results 1 - 6 of 6
EC Number Reaction Commentary Reference
Display the word mapDisplay the reaction diagram Show all sequences 1.2.1.30an aromatic aldehyde + NADP+ + AMP + diphosphate = an aromatic acid + NADPH + H+ + ATP - -
Display the word mapDisplay the reaction diagram Show all sequences 1.2.1.30an aromatic aldehyde + NADP+ + AMP + diphosphate = an aromatic acid + NADPH + H+ + ATP carboxylic acid and ATP are first bound in the A-domain, wherein the alpha-phosphate of ATP is attacked by the acid, releasing diphosphate and forming an acyl-adenylate complex. The CAR enzyme then undergoes a domain shift into a thiolation state where the adenylate is then attacked by the thiol group on the phosphopantetheine arm at the carbonyl carbon, forming a thioester and releasing AMP. The CAR enzyme then undergoes another domain shift where the phosphopantetheine arm is exposed in the R-domain. Finally, the thioester is reduced by NADPH, producing the aldehyde product while returning the phosphopantetheine arm to its thiol form 763297
Display the word mapDisplay the reaction diagram Show all sequences 1.2.1.30an aromatic aldehyde + NADP+ + AMP + diphosphate = an aromatic acid + NADPH + H+ + ATP carboxylic acid and ATP are first bound in the A-domain, wherein the alpha-phosphate of ATP is attacked by the acid, releasing pyrophosphate and forming an acyl-adenylate complex. The CAR enzyme then undergoes a domain shift into a thiolation state where the adenylate is then attacked by the thiol group on the phosphopantetheine arm at the carbonyl carbon, forming a thioester and releasing AMP. The CAR enzyme then undergoes another domain shift where the phosphopantetheine arm is exposed in the R-domain. Finally, the thioester is reduced by NADPH, producing the aldehyde product while returning the phosphopantetheine arm to its thiol form -, 763297
Display the word mapDisplay the reaction diagram Show all sequences 1.2.1.30an aromatic aldehyde + NADP+ + AMP + diphosphate = an aromatic acid + NADPH + H+ + ATP product inhibition by NADP+, adenosine monophosphate, and diphosphate indicates that the binding of substrates at the adenylation domain is ordered with ATP binding first, proposed catalytic mechanism in 4 steps, overview. The first two steps, the relatively unreactive carboxylic acid is activated to form a thioester with the phosphopantetheine arm at the N-terminal adenylation domain (1) ATP and a carboxylic acid enter the active site of the adenylation domain in which the alpha-phosphate of ATP is attacked by an O atom from the carboxylic acid to form an AMP-acyl phosphoester with the release of diphosphate.(2) The thiol group of the phosphopantetheine arm can then attack the carbonyl carbon atom of the AMP-acyl phosphoester intermediate nucleophilically to release AMP and to form an acyl thioester with the phosphopantetheine arm. (3) The phosphopantetheine arm transfers to the C-terminal reductase domain in which (4) the thioester is reduced by NADPH, the aldehyde and NADP+ are released, and the thiol of the phosphopantetheine arm is regenerated in the process -, 762919
Display the word mapDisplay the reaction diagram Show all sequences 1.2.1.30an aromatic aldehyde + NADP+ + AMP + diphosphate = an aromatic acid + NADPH + H+ + ATP product inhibition by NADP+, adenosine monophosphate, and diphosphate indicates that the binding of substrates at the adenylation domain is ordered with ATP binding first, proposed catalytic mechanism in 4 steps, overview. The first two steps, the relatively unreactive carboxylic acid is activated to form a thioester with the phosphopantetheine arm at the N-terminal adenylation domain (1) ATP and a carboxylic acid enter the active site of the adenylation domain in which the alpha-phosphate of ATP is attacked by an O-atom from the carboxylic acid to form an AMP-acyl phosphoester with the release of diphosphate.(2) The thiol group of the phosphopantetheine arm can then attack the carbonyl carbon atom of the AMP-acyl phosphoester intermediate nucleophilically to release AMP and to form an acyl thioester with the phosphopantetheine arm. (3) The phosphopantetheine arm transfers to the C-terminal reductase domain in which (4) the thioester is reduced by NADPH, the aldehyde and NADP+ are released, and the thiol of the phosphopantetheine arm is regenerated in the process 762919
Display the word mapDisplay the reaction diagram Show all sequences 1.2.1.30an aromatic aldehyde + NADP+ + AMP + diphosphate = an aromatic acid + NADPH + H+ + ATP the catalytic cycle starts with the activation of the carboxylate substrate with ATP in the A-domain, yielding an AMP-ester intermediate under release of pyrophosphate as the co-product. The active thiol tether of the phosphopantetheinyl moiety then binds the carboxylate, releasing AMP as a leaving group. The resulting thioester is subsequently transferred to the R domain, where it is reduced to the corresponding aldehyde product. The aldehyde is not amenable to enter a second catalytic cycle. The enzyme does not catalyze the overreduction of the aldehyde product to the respective alcohol -, 763290
Results 1 - 6 of 6